JSM Learn JSM Learn
       
 
 
 
 
 
 

Q. If the solubility product of AB2 is 3.20 × 10-11 M3, then the solubility of AB2 in pure water is..... × 10-4 mol L-1 [Assuming that neither kind of ion reacts with water].

 

Ans. 2

Explanation:

AB2(s) ⇌ A(aq.)+2+2B(aq.)-                S        2S

Ksp = [A+2][B-]2 = S(2S)2

⇒ 4S3  = 32 × 10–12

∴ S = 2 × 10–4 mol/lit