JSM Learn - Q. pH of a saturated solution of Ca(OH)2 is 9. The solubility product (Ksp) of Ca(OH)2 is:     (1) 0.5 × 10–15                                       (2) 0.25 × 10–10     (3) 0.125 × 10–15                                  (4) 0.5 × 10

Q. p^H of a saturated solution of Ca(OH)₂ is 9. The solubility product (K_sp) of Ca(OH)₂ is:

(1) 0.5 × 10^–15 (2) 0.25 × 10^–10

(3) 0.125 × 10^–15 (4) 0.5 × 10^–10

Ans. (1)

Explanation:

$Ca {(OH)}_{2} ⇋ {Ca}^{2 +} + 2 {OH}^{-} S 2 S p^{H} = 9 So p^{OH} = 14 - 9 = 5 (∵ p^{H} + p^{OH} = 14) ∴ [{OH}^{-}] = 2 S = 10^{- 5} M (∵ [{OH}^{-}] = 10^{- p^{OH}}) [{Ca}^{2 +}] = S = \frac{10^{- 5}}{2} K_{sp} = [{Ca}^{2 +}] {[{OH}^{-}]}^{^{2}} = (\frac{10^{- 5}}{2}) {(10^{- 5})}^{2} = 0.5 \times 10^{- 15}$

Q. p^H of a saturated solution of Ca(OH)₂ is 9. The solubility product (K_sp) of Ca(OH)₂ is:

(1) 0.5 × 10^–15 (2) 0.25 × 10^–10

(3) 0.125 × 10^–15 (4) 0.5 × 10^–10

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Q. pH of a saturated solution of Ca(OH)2 is 9. The solubility product (Ksp) of Ca(OH)2 is: (1) 0.5 × 10–15 (2) 0.25 × 10–10 (3) 0.125 × 10–15 (4) 0.5 × 10–10

Q. p^H of a saturated solution of Ca(OH)₂ is 9. The solubility product (K_sp) of Ca(OH)₂ is:

(1) 0.5 × 10^–15 (2) 0.25 × 10^–10

(3) 0.125 × 10^–15 (4) 0.5 × 10^–10